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X=-3X+5X^2
We move all terms to the left:
X-(-3X+5X^2)=0
We get rid of parentheses
-5X^2+3X+X=0
We add all the numbers together, and all the variables
-5X^2+4X=0
a = -5; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-5)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-5}=\frac{-8}{-10} =4/5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-5}=\frac{0}{-10} =0 $
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